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(C) The shearing stress is defined as the ratio of the shearing force to the area of the surface parallel to the force.Given,shearing strength (maximu

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$13800$

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(C) The shearing stress is defined as the ratio of the shearing force to the area of the surface parallel to the force.Given,shearing strength (maximum shearing stress) $	au_{max} = 345 \, MN/m^2 = 345 	imes 10^6 \, N/m^2$.The area of the face $ABCD$ subjected to shear is $A = BC 	imes BE = 2 \, cm 	imes 2 \, cm = 4 \, cm^2 = 4 	imes 10^{-4} \, m^2$.The maximum shearing force $F$ that the rod can withstand is $F = 	au_{max} 	imes A$.$F = (345 	imes 10^6 \, N/m^2) 	imes (4 	imes 10^{-4} \, m^2) = 345 	imes 4 	imes 10^2 \, N = 138000 \, N$.Since $F = mg$,where $m$ is the mass of the load and $g = 10 \, m/s^2$:$m = F / g = 138000 / 10 = 13800 \, kg$.Thus,the maximum load is $13800 \, kg$.

$A$ steel rod is projecting out of a rigid wall. The shearing strength of steel is $345 \, MN/m^2$. The dimensions are $AB = 5 \, cm$ and $BC = BE = 2 \, cm$. The maximum load that can be put on the face $ABCD$ is .......... $kg$ (neglect bending of the rod). Take $g = 10 \, m/s^2$.

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